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  4. » Linear stage motorization

 
Linear stage motorization...

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Linear stage motorization sent on October 24, 2022 (17:27) by Luciano Bersani. 7 comments, 432 views. [retina]

at 35mm, 1/100 f/6.3, ISO 200, hand held.

Questo linear stage motorizzato lo posso usare anche sul campo. Il passo del motore è di 1,8°, con il controller Wemacro in teoria posso fare uno spostamento minimo di 0,65µm.



View High Resolution 15.9 MP  



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avatarsenior
sent on November 12, 2022 (17:06) | This comment has been automatically translated (show/hide original)

Congratulations Luciano, interesting. Have a nice weekend

avatarjunior
sent on November 13, 2022 (18:02) | This comment has been automatically translated (show/hide original)

Thank you. However, I
have verified in practice that the minimum displacement is 0.5?m.
I'm puzzled, the Wemacro information says that the value of 4?m corresponds to a step, or 800?m to make a complete turn (500?m / 800 = 0.625?m, not 0.65?m as I mistakenly wrote): I have to put 1000?m to make a complete turn
.

avatarsenior
sent on June 22, 2023 (15:12) | This comment has been automatically translated (show/hide original)

Hello Luciano ... I read your comment and tried to understand.
So, Wemacro says that the motor has a minimum pitch of 1.8°, so it is able to divide the 360° turn angle into 200 steps. (360.0/1.8=200) consequently the minimum feed will depend on how far the micrometer advances in a single turn divided by 200... I
did something wrong or I didn't understand the problem.
Best regards Gianka

avatarjunior
sent on June 23, 2023 (12:50) | This comment has been automatically translated (show/hide original)

Now I changed the engine with one of 400 steps-turn, or 0.9 ° per step. Wemacro has stated that its controller divides each step into 4 micro steps and each micro step, with its motorized slide, corresponds to 1 ?m of advancement: the motor used by Wemacro is 400 steps. I have verified that, driving a 0.5mm micrometer per revolution with a 400-step stepper (0.9°), to make a complete turn, in the controller App, I must enter the 2000?m value in the step length box. So a complete turn is 400 steps and 2000/400 = 5, that is, a step of the engine is divided into 5 micro steps and not 4. I hope I have been clear and have not generated confusion, I still have no specific knowledge in the field of electric motors (and not).
Greetings

avatarjunior
sent on January 14, 2024 (9:19) | This comment has been automatically translated (show/hide original)

Oh my goodness what equipment, congratulations really.
I also have the WeMacro and I'm happy with it, but in the mobile app you can only set 0.01 which corresponds to 10 microns, how do you set 1 micron (which should be able to handle the slide) which corresponds to 0.001?

avatarjunior
sent on January 14, 2024 (15:23) | This comment has been automatically translated (show/hide original)


avatarjunior
sent on January 14, 2024 (15:33) | This comment has been automatically translated (show/hide original)

Clearly, driving a "linear stage" (in good condition) with a micrometric head with a stepper gives much more precise displacements than the Wemacro sled, especially with regard to the parallelism of the displacements.
The minimum distance that can be set is found by dividing the distance traveled with a complete revolution (500?m in the set-up in the photo) with the steps of the motor (400 or 200) multiplied by the number of microsteps, in this case: 500?m/(400x5) = 0.25?m




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